Area - Arithmetic Aptitude Questions and Answers

Home / Arithmetic Aptitude / Area :: Discussion

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:

40%

42%

44%

46%

Answer : Option C

Explanation :

Let original length = x metres and original breadth = y metres.

Original area = (xy) m².

New length= $[\frac { 120 } { 100 }$ x]m= $[ \frac {6 } { 5 }X ]$ m

New breadth = $[\frac { 120 } { 100 }$ y]m= $[ \frac {6 } { 5 }Y ]$ m

New Area =[ $\frac {6 } { 5 }XX$ $\frac {6 } { 5 }Y ]$ $m^2$ = $[ \frac {36 } {2 5 }XY ]$ $m^2$

The difference between the original area = xy and new-area 36/25 xy is

= (36/25)xy - xy

= xy(36/25 - 1)

= xy(11/25) or (11/25)xy

Increase % =[ $\frac {11 } { 25 }XY$ x $\frac { 1 } { XY }$ x100]%=44%

Be The First To Comment

Comments

Name