Answer : Option B
Explanation :
Pervez can complete the work in 20 days
Sunny can complete the same job in 15 days
Let the total work = LCM of both
Therefore, the LCM of 20 and 15 is 60, that means total work = 60 units
Now, Pervez's one-day work efficiency = 60/20 = 3 units
Sunny's one-day work efficiency = 60/15 = 4 units
ATQ, (Pervez+Sunny) together works for 6 days
That means (Pervez+Sunny) have done 7*6 = 42 units work in 6 days
Now, the remaining work will be 60-42 = 18 units, and it will finish in 4 days.
Now, Sunny is replaced with Ashu:
So, per days work required to be finished = 18 units / 4 days = 4.5 units
But, we know that Pervez's one-day work = 3 units, so Ashu's one-day work = 4.5-3 = 1.5 units
Therefore, Ashu alone can finish the total work in 60 units /1.5 days = 40 days
of the time limit had expired, he found that 
of the originally assigned work had been already completed. The number of laborers who could be removed by the contractor for this project so that the project could be completed by the remaining laborers within the given time limit would be 
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