Decimal Fraction - Arithmetic Aptitude Questions and Answers

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The value of $\frac {(0.96)^3-(0.1)^3 } { (0.96)^2+0.096+(0.1)^2}$ is:

0.86

0.95

0.97

1.06

Answer : Option A

Explanation :

Given expression= $\frac {(0.96)^3-(0.1)^3 } { (0.96)^2+(0.96*0.1)+(0.1)^2}$

= $[ \frac { a^3-b^3} { a^2+ab+b^2 }]$

=(a - b)

=(0.96-01)

=0.86

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