The rational number for recurring decimal 0.125125.... is:
\( \frac { 63 } { 487 }\)
\(\frac { 119 } { 993 }\)
\(\frac { 125 } { 999}\)
None of these
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Answer : Option C
Explanation :
0.125125... = \(\bar0.125\)=\(\frac { 125 } { 999}\)
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