Height and Distance - Arithmetic Aptitude Questions and Answers

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Discussion :: Height and Distance

From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

149 m

156 m

173 m

200 m

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Answer : Option A

Explanation :

Let AB be the tower.

Then, APB = 30° and AB = 100 m.

	$\frac { AB } { AP }$ = tan 30° = $\frac { 1 } { 3 }$
	$\frac { AB } { AP }$ = tan 30° = $\frac { 1 } { 3 }$

AP	= (AB x 3) m
	= 1003 m
	= (100 x 1.73) m
	= 173 m

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