If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
2.870
2.967
3.876
3.912
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Answer : Option C
Explanation :
=log29log(10/2)
=9log2log10−log2
=(9∗0.301001−0.3010
=2.7090.699
=2.709699
= 3.876
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