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Discussion :: Numbers

  1. If n is a natural number, then (6n2 + 6n) is always divisible by:

    2. A.

    6 only
    B.

    6 and 12 both
    C.

    12 only
    D.

    by 18 only

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    Answer : Option B

    Explanation :

    (6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.

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