Discussion :: Numbers
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\([1- \frac { 1 } { n }]\)+\([1- \frac {2 } { n}]\)+\([1- \frac { 3 } { n } ] \)+.... up to n terms=?
A.
\(\frac { 1 } { 2 }n\) |
B.
\(\frac { 1 } { 2 }(n-1)\) |
C.
\(\frac { 1 } { 2 }n(n-1)\) |
D.
None of these |
Answer : Option B
Explanation :
....to n terms
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\( n- \frac { n+1} { 2 } \)
\( \frac { 1 } { 2 } (n-1)\) |
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