Numbers - Arithmetic Aptitude Questions and Answers

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$[1- \frac { 1 } { n }]$ + $[1- \frac {2 } { n}]$ + $[1- \frac { 3 } { n } ]$ +.... up to n terms=?

$\frac { 1 } { 2 }n$

$\frac { 1 } { 2 }(n-1)$

$\frac { 1 } { 2 }n(n-1)$

None of these

Answer : Option B

Explanation :

....to n terms

Given sum= (1+1+1+...to n terms)- $[\frac { 1 } { n} +$

$\frac {2} {n}+$

$\frac {3 } { n }+$

$n- \frac {n } { 2 }$ $[\frac { 1 } { n } +1]$

$n- \frac { n+1} { 2 }$

$\frac { 1 } { 2 } (n-1)$

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