Home / Arithmetic Aptitude / Numbers :: Discussion

Discussion :: Numbers

  1. A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:

  2. A.

    214

    B.

    476

    C.

    954

    D.

    1908

    View Answer

    Workspace

    Answer : Option A

    Explanation :

    4 | x            z = 6 x 1 + 4  = 10
     -----------
     5 | y -2         y = 5 x z + 3  = 5 x 10 + 3  = 53
     -----------
     6 | z - 3        x = 4 x y + 2  = 4 x 53 + 2  = 214
     -----------
       | 1 - 4
       
    Hence, required number = 214.


Be The First To Comment