Discussion :: Numbers
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The sum of first 45 natural numbers is:
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Answer : Option A
Explanation :
Let Sn = (1 + 2 + 3 + ... + 45)
This is an A.P. in which a = 1, d = 1, n = 45 and l = 45
Sn =\(\frac { n } { 2 } (a+1)\)=\( \frac { 45 } { 2 }\)x (1 + 45) = (45 x 23) = 1035
Required sum = 1035.
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