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Discussion :: Percentage

  1. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
    2. A.

    39, 30
    B.

    41, 32
    C.

    42, 33
    D.

    43, 34

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    Answer : Option C

    Explanation :

    Let their marks be (x + 9) and x.

     

     Then, x +9 = \( \frac { 56} { 100 } \)(x+9+x)

     25(x + 9) = 14(2x + 9)

     3x = 99

     x = 33

     

    So, their marks are 42 and 33.

     

     

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