Pipes and Cistern - Arithmetic Aptitude Questions and Answers

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Discussion :: Pipes and Cistern

A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?

15 min

20 min

27.5 min

30 min

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Answer : Option D

Explanation :

Part filled by (A + B) in 1 minute = [ $\frac { 1 } { 60 }$ + $\frac { 1 } { 40 } ]$ = $\frac { 1 } {24 }$

Suppose the tank is filled in x minutes.

Then, $\frac { X} { 2 }$ [ $\frac { 1 } {24 }$ + $\frac { 1 } { 40 } ]$ =1

$\frac { X} { 2 }$ X $\frac { 1 } {15 }$ =1

x = 30 min.

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