Discussion :: Probability
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Two dice are tossed. The probability that the total score is a prime number is:
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A.
\(\frac { 1 } { 6 } \) |
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B.
\( \frac { 5 } { 12 } \) |
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C.
\(\frac { 1 } { 2 } \) |
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D.
\(\frac { 7 } { 9} \) |
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Answer : Option B
Explanation :
Clearly, n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.
| Then E | = { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5) } |
n(E) = 15.
P(E) = \(\frac { n(E) } { n (S)} \) =\( \frac { 15 } { 36 }\)=\( \frac { 5 } { 12 } \)
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