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  1. The tickets numbered from 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket has a number which is a multiple of 3 or 5?

    2. A.
    9/20
    B.
    9/24
    C.
    9/27
    D.
    9/30

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    Answer : Option A

    Explanation :

    The sample space, S= (1, 2, 3, 4, 5 ...18, 19, 20) or n(S) = 20

    The event "E" of getting a multiple of 3 or 5 = (3, 6, 9, 12, 15, 18, 5, 10, 20) or n (E) = 9
    So, the probability of getting multiple of 3 or 5, P (E) = = 9/20

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