Problems on Ages - Arithmetic Aptitude Questions and Answers

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A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?

38 years

40 years

43 years

45 years

Answer : Option D

Explanation :

Let the age of son = X years

∴Age of mother would be =2X

As per question 20 years ago;

10 (X -20) = 2X - 20

10X - 200 = 2X - 20

10X - 2X= - 20 + 200

8X = 180

X== 22.5 years

∴Age of mother = 22.5 * 2 = 45 years

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