Discussion :: Problems on Ages
- The ratio of the ages of Seeta and Geeta is 2:7. After 6 years, the ratio of their ages will be 1:2. What is the difference in their present ages?
Answer : Option C
Explanation :
Let the age of Seeta is 2X and age of Geeta 7X.
As per question after 6 years;
4X +12 = 7X + 6
-3X = -6
X = 2
∴Age of Seeta = 2 * 2 = 4 years
Age of Geeta = 7 * 2 = 14 years
Difference in their ages = 14 - 4 = 10 years
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