Discussion :: Problems on Ages
- The sum of the ages of father and his son is 44 years. If 6 years after the father will be 3 times as old as his son, what are their present ages?
Answer : Option A
Explanation :
Let present age of son is X and present age of father is (44 -X).
As per question, after 6 years;
3(X+6) = (44 - X) +6
3X +18 = 50 - X
4X = 50 - 18
4X = 32
X = 8 years
∴Present age of son = 8 years
And, present of father = 44 - 8 = 36 years
Solution 2;
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