Discussion :: Problems on Trains
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A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Answer : Option D
Explanation :
Let the speed of the second train be x km/hr.
Relative speed | = (x + 50) km/hr |
= \(\left(( { x +50 } ) \times(\frac{5}{18})\right)m/sec\) | |
= \(\left(\frac{250+5x}{18}\right)m/sec\) |
Distance covered = (108 + 112) = 220 m.
\(\frac{220}{\left(\frac{250+5x}{18}\right)}=6\)
250 + 5x = 660
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