Profit and Loss - Arithmetic Aptitude Questions and Answers

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A dishonest milkman sells milk at cost price, but he mixes water and earns 16(2/3) % profit. Find the ratio of mixture and milk in the mixture.

7: 5

7: 6

7: 7

7: 8

Answer : Option D

Explanation :

Solution 1:

Let C.P of 1-litre milk = 10
Brought milk = x liters
Then C.P = 10x
Let water mixed in milk = y liter
Then quantity of mixture = (x+y) liter

Mixture is sold on C.P
Then S.P = 10(x + y)
= 10x + 10y

The profit = S.P- C.P = (10x + 10y) - 10x
= 10y
Profit % = (10y/10x)*100 = 16(2/3) %

Or, y/x = (50/3)*(1/100)
Or, y/x = (50/300)
Or, y/x = (1/6)
So, mixture = x+y = 6+1 = 7
Then, (mixture/milk) = 7/6 or 7:6

Apply formula:

Solution 2:

16(2/3) % profit = (50/3)*(1/100) = 1/6
i.e., +1>water
6> milk
That means if the total mixture is 6+1 = 7
Then milk = 6
Mixture: milk = 7: 6

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