Simplification - Arithmetic Aptitude Questions and Answers

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A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

30 birds

60 birds

72 birds

90birds

Answer : Option A

Explanation :

Let the total number of shots be x. Then,

shots fired by A= $\frac { 5 } { 8 } X$

shots fired byB= $\frac { 3 } { 8 } X$

Killing shots by A = $\frac { 1 } { 3 }$ of $\frac { 5 } { 8 } X$ = $\frac { 5} { 24 }X$

Shots missed by B = $\frac { 1 } { 2 }$ of $\frac { 3 } { 8 } X$ = $\frac { 3 } { 16 }X$

$\frac { 3X } { 16 }$ =27or X= $[\frac { 27*16 } {3}]$ =144

Birds killed by A = $\frac { 5X} { 24 }$ = $[ \frac { 5 } { 24 }*144]$ =30

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