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Discussion :: Square Root and Cube Root

  1. If x =√3+1√3−1 and  Y = √3−1√3+1 ,then the value of (x2 + y2) is:

    2. A.

    10
    B.

    13
    C.

    14
    D.

    15

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    Answer : Option C

    Explanation :

    X = (√3+1)(√3−1) x (√3+1)(√3+1) = (√3+1)2(3−1) = 3+1+2√32 = 2+√3

     

    y =  (√3−1)(√3+1) x (√3−1)(√3−1) = (√3−1)2(3−1)= 3+1−2√32= 2 -√3

     

     x2 + y2 = (2 +√3 )2 + (2 - √3)2

     

          = 2(4 + 3)

      

           = 14

     

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