Discussion :: Square Root and Cube Root
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If \(\sqrt{5}\)= 2. 236 , then value of \(\frac {\sqrt{5} } { 2 }\)- \(\frac {10 } { \sqrt{5} }\)+ \(\sqrt{125}\) is equal to :
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Answer : Option B
Explanation :
\(\frac {\sqrt{5} } { 2 }\)-\(\frac {10 } { \sqrt{5} }\)+\(\sqrt{125}\) =\(\frac {( \sqrt{5})^2-20 +2\sqrt{5}*5\sqrt{5}} { 2 \sqrt{5}} \)
= \(\frac { 5- 20 +50 } { 2\sqrt{5} } \)
= \(\frac {35} { 2\sqrt{5} } \) x \(\frac {\sqrt{5}} { \sqrt{5} } \)
= \(\frac {35\sqrt{5}} {10 } \)
= \(\frac { 7*2.236 } { 2 } \)
= 7 x 1.118
= 7.826
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