Discussion :: Square Root and Cube Root
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If x = √3 + 1 and y = √3 - 1 , then the value of (x2 + y2) is: √3 - 1 √3 + 1
Answer : Option C
Explanation :
x = | (√3 + 1) | x | (√3 + 1) | = | (√3 + 1)2 | = | 3 + 1 + 2√3 | = 2 + √3. |
(√3 - 1) | (√3 + 1) | (3 - 1) | 2 |
y = | (√3 - 1) | x | (√3 - 1) | = | (√3 - 1)2 | = | 3 + 1 - 2√3 | = 2 - √3. |
(√3 + 1) | (√3 - 1) | (3 - 1) | 2 |
x2 + y2 = (2 + √3)2 + (2 - √3)2
= 2(4 + 3)
= 14
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