Surds and Indices - Arithmetic Aptitude Questions and Answers

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$\frac { 1 } { 1+a^(n-m) } +$ $\frac { 1 } { 1+a^(m-n) }=?$

$\frac { 1 } { 2 }$

a^m + n

Answer : Option C

Explanation :

$\frac { 1 } { 1+a^(n-m) } +$ $\frac { 1 } { 1+a^(m-n) }=$ $\frac { 1 } {[1+ a^n/a^m]}+$ $\frac { 1 } {[1+ a^m/a^n]}$

= $\frac {a^m } { (a^m+a^n)}$ + $\frac {a^n } { (a^m+a^n)}$

= $\frac { (a^m+a^n) } { (a^m+a^n)}$

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