Discussion :: Time and Distance
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Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
Answer : Option C
Explanation :
Let the distance travelled by x km.
Then,\( \frac { X } { 10 }-\)\( \frac { X } { 15 }\)=2
3x - 2x = 60
x = 60 km.
Time taken to travel 60 km at 10 km/hr =\([\frac { 60 } { 10 } ]\)hrs=6hrs.
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
Required speed =\([\frac { 60 } { 5 } ]\)kmph=12 kmph.
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