Discussion :: Time and Distance
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A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
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Answer : Option D
Explanation :
Let distance = x km and usual rate = y kmph.
Then,\(\frac { X} { Y}\)-\( \frac { X } { Y+3 }\)=\(\frac { 40 } { 60 } \)
2y(y + 3) = 9x ....(i)
And,\( \frac { X } { Y-2 }\)-\(\frac { X} { Y}\)=\(\frac { 40 } { 60 } \) y(y - 2) = 3x ....(ii)
On dividing (i) by (ii), we get: x = 40.
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