Time and Work - Arithmetic Aptitude Questions and Answers

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Discussion :: Time and Work

A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?

23 days

37 days

37 $\frac { 1 } { 2 }$

40 days

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Answer : Option C

Explanation :

Whole work is done by A in[ $[20*\frac { 5 } {4 } ]$ = 25 days.

Now,[1- $\frac { 4 } { 5 }$ ]i.e., $\frac {1 } { 5 }$ work is done by A and B in 3 days

Whole work will be done by A and B in (3 x 5) = 15 days.

A's 1 day's work = $\frac {1 } { 25 }$ ,, (A + B)'s 1 day's work = $\frac {1 } { 15 }$

B's 1 day's work =[ $\frac {1 } { 15 }$ - $\frac {1 } { 25 }$ ]= $\frac {4 } { 150 }$ = $\frac {2 } { 75 }$

So, B alone would do the work in $\frac {75 } { 2 }$ =37 $\frac { 1 } { 2 }$ days

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