Discussion :: Time and Work
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A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer : Option C
Explanation :
B's 10 day's work =[115∗10]=23
Remaining work =[1-23]=13
Now, 118 work is done by A in 1 day.
13work is done by A in[18x13]=6 days
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