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Discussion :: Time and Work

  1. A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?

    2. A.

    5
    B.

    5\( \frac { 1 } { 2 } \)
    C.

    6
    D.

    8

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    Workspace

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    Answer : Option C

    Explanation :

    B's 10 day's work =[\( \frac { 1 } { 15 }*10]\)=\( \frac { 2 } { 3} \)

     

    Remaining work =[1-\( \frac { 2 } { 3} \)]=\( \frac { 1 } { 3} \)

     

    Now,   \( \frac { 1 } { 18} \)   work is done by A in 1 day.

     

    Therefore\( \frac { 1 } { 3} \)work is done by A in[18x\( \frac { 1 } { 3} \)]=6 days

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