Time and Work - Arithmetic Aptitude Questions and Answers

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Discussion :: Time and Work

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:

5 days

6 days

10 days

10 $\frac { 1 } { 2 }$ days

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Answer : Option C

Explanation :

(B + C)'s 1 day's work = $[ \frac { 1 } { 9 }+$ $\frac { 1 } {1 2 }]$ = $\frac { 7 } { 36 }$

Work done by B and C in 3 days =[ $\frac { 7 } { 36 } *3]$ = $\frac { 7 } {1 2 }$

Remaining work =[1- $\frac { 7 } {1 2 }$ ]= $\frac { 5 } {1 2 }$

Now, $\frac { 1 } { 24 }$ work is done by A in 1 day

So, $\frac { 5 } {1 2 }$ work is done by A in[ $24*\frac { 5 } {1 2 } ]$ =10days

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