Discussion :: Time and Work
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X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they together take to complete the work?
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Answer : Option A
Explanation :
| Work done by X in 8 days = |  | 1 | x 8 |  | = | 1 | . |
| 40 | 5 |
| Remaining work = | | 1 - | 1 | | = | 4 | . |
| 5 | 5 |
| Now, | 4 | work is done by Y in 16 days. |
| 5 |
| Whole work will be done by Y in | | 16 x | 5 | | = 20 days. |
| 4 |
 X's 1 day's work = | 1 | , Y's 1 day's work = | 1 | . |
| 40 | 20 |
| (X + Y)'s 1 day's work = | | 1 | + | 1 | | = | 3 | . |
| 40 | 20 | 40 |
| Hence, X and Y will together complete the work in | 40 | | = 13 | 1 | days. | |
| 3 | 3 |
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