Discussion :: Time and Work
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A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :
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Answer : Option C
Explanation :
| (A + B)'s 1 day's work = |  | 1 | + | 1 |  | = | 1 | . |
| 15 | 10 | 6 |
| Work done by A and B in 2 days = | | 1 | x 2 | | = | 1 | . |
| 6 | 3 |
| Remaining work = | | 1 - | 1 | | = | 2 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 15 |
 | 2 | work will be done by a in | | 15 x | 2 | | = 10 days. |
| 3 | 3 |
Hence, the total time taken = (10 + 2) = 12 days.
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