Discussion :: Time and Work
- Two men do a piece of work for rupees 200. One alone can finish the work in 6 days, and the other can finish it in 8 days. With the help of a boy, they finish it in 3 days. How much money should be given to the boy?
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Answer : Option B
Explanation :
A can finish the work in 6 days, and B can finish the work in 8 days.
(A+B+C) can finish it in 3 days.
Now, A = 6 days
B = 8 days
A+B+C = 3 days
Note: Assume the total work = LCM of the given days
Take the LCM of days = LCM of (6, 8, and 3) = 24
Let the total work = 24
Or, A's one day work = 24/6=4
B's one day work = 24/8=3
(A+B+C)'s one day work = 24/3=8
Then, C's one day work = 4+3+C = 8, or C=1
Or, A: B: C = 4:3:1
Total money = 200
C's share = [C's one day work/ one day work of (A+B+C)]* total money
C's share = [1/8] * 200 = 25
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