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Discussion :: Chemical Engineering Thermodynamics

  1. The Maxwell relation derived from the differential expression for the Helmholtz free energy (dA) is

    2. A.

     (∂T/∂V)S = -(∂P/∂S)V
    B.

     (∂S/∂P)T = -(∂V/∂T)P
    C.

     (∂V/∂S)P = (∂T/∂P)S
    D.

     (∂S/∂V)T = (∂P/∂T)V

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    Answer : Option D

    Explanation :

    Helmholtz function :
    A=U−TS⇒dA=−PdV−SdT
    So, we can derive the Maxwell function : (∂P∂T)V=(∂S∂V)T

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