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  1. For spontaneous changes in an isolated system (S = entropy)

    2. A.

     Ds = 0
    B.

     Ds <0
    C.

     Ds > 0
    D.

     Ds = Constant

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    Answer : Option C

    Explanation :

    By second law of thermodynamics the TdS≥δQ
    For an isolated system δQ=0
    ⇒ for an irreversible (nothing but spontaneous process) dS>0   and for an reversible (or the system at equilibrium) dS=0

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