Discussion :: Chemical Engineering Thermodynamics
- In any spontaneous process,
Answer : Option C
Explanation :
For any spontaneous process there should be finite changes so, we can consider it as an irreversible process and we know for irreversible process from second law of thermodynamics TdS−dU−PdV>0
Under constant temperature and volume process −dF>0⇒dF<0
Similarly for an constant temperature and pressure process
d(TS−U−PV)>0⇒dG=0
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