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In a working refrigerator, the value of COP is always

< 0

< 1

> 1

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Answer : Option D

Explanation :

We know COP of a refrigerator
$\eqalign{ & = \frac{{{\text{Cooling effect}}}}{{{\text{Work taken}}}} \cr & = \frac{{{Q_L}}}{{{W_{net}}}} \cr & = \frac{{{Q_2}}}{{{Q_1} - {Q_2}}} \cr}$
For a reversible refrigerator COP $= \frac{{{T_2}}}{{{T_1} - {T_2}}}$
Since ${T_1} - {T_2} < {T_2}$
So COP is always greater than zero.

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