Discussion :: Applied Mechanics
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If the velocity of projection is 4 m/sec and the angle of projection is 뱡, the maximum height of the projectile from a horizontal plane, is
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A.
\(\frac { u^2 cos^2a } { 2g } \) |
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B.
\(\frac { u^2 sin^2a } { 2g } \) |
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C.
\(\frac { u^2 tan^2a } { 2g } \) |
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D.
\(\frac { u^2 sin2a } { 2g } \) |
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Answer : Option B
Explanation :
No answer description available for this question
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