Hydraulics - Civil Engineering Questions and Answers

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Critical depth (h) of a channel, is

h = $\frac { v^2 } { g }$

h = $\frac { v^2 } { 2g }$

h = $\frac { v } {2 g }$

h = $\frac { v } {g }$

Answer : Option A

Explanation :

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