Discussion :: Hydraulics
-
A pipe consisting of several pipes of varying diameters and lengths, may be replaced by an equivalent pipe of diameter D of length
A.
L = \(D^4\) [ \(\frac { l1 } { d1^4 } \)+\(\frac { l2 } { d2^4 } \)+\(\frac { l3 } { d3^4 } \)+......] |
B.
L =\(D^3\) [\(\frac { l1 } { d1^3} \)+\(\frac { l2 } { d2^3 } \)+\(\frac { l3 } { d3^3 } \)+......] |
C.
L = \(D^5\)[ \(\frac { l1 } { d1^5 } \)+\(\frac { l2 } { d2^5 } \)+\(\frac { l3 } { d3^5 } \)+......] |
D.
L = \(D^2\)[ \(\frac { l1 } { d1^2 } \)+\(\frac { l2 } { d2^2 } \)+\(\frac { l3 } { d3^2} \)+.....] |
Answer : Option C
Explanation :
No answer description available for this question.
Be The First To Comment