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The ratio of time for completely emptying the hemispherical tank and circular horizontal tank of equal radii both fitted with similar orifices at their bottoms is :

$\frac { n } { 3 }$ $[\frac { (4/3RH1^3/2 -2/5H^3/2} {( 2R)^3/2-(2R-H1)^3/2 } ]$

$\frac { n } {2 }$ $[\frac { (2/5RH1^3/2 -2/3H^3/2} {( 3R)^3/2-(2R-H1)^3/2 } ]$

$\frac { n } { 3 }$ $[\frac { (4/3)RH1^3/2 +2/5H^5/2} {( R)^3/2-(2R+H)^3/2 } ]$

n $[\frac { (2/3)RH1^3/2 +2/5H^2/5} {( R)^3/4+(4R+H1)^3/2 } ]$

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Answer : Option A

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