Hydraulics - Civil Engineering Questions and Answers

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If a₁ and a₂ are the cross-sectional areas of a tank and orifice, h the height of water level in tank above the centre of the orifice, the velocity of approach is given by

v = $\sqrt[]\frac { 2gh } { 1-a2^2/a1} )$

v = $\sqrt{}1-\frac { \partial2^2 } {\partial1^2 }$

v= $\sqrt[]\frac { 2gh } { 1-\partial1^2/a2^2} )$

v= $\sqrt[]\frac { 2gh } { 1-\partial1^1/a1^2} )$

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Answer : Option A

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