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Fundamental momentum equation for a hydraulic jump, is
A.
D12−D12=2qg(v1−v2) |
B.
D22−D12=2qg(v−v2) |
C.
D12−D22=2qg(v2−v1) |
D.
D12+D22=2qg(v2−v1) |
Answer : Option B
Explanation :
No answer description available for this question.