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If D_c is the critical depth, D is the depth of water down stream and H_L is the total head loss at the cistern of a vertical fall, the depth x of the cistern below the bed level down stream suggested by Blench, is

Dc- D + $\frac { 1 } { 4}$ [HL- $\frac { 3} { 8} Dc$ ]

2 Dc - D + $\frac { 1 } { 4}$ [ HL- $\frac { 3} { 8} Dc$ ]

2 Dc - D + $\frac { 3 } { 8}$ [ Hc - $\frac { 1 } { 4}$ Dc]

3Dc -D + $\frac { 3 } { 8}$ [ HL - $\frac { 1 } { 4}$ Dc]

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Answer : Option B

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