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If d is the distance between equidistant odd ordinates, the Simpson's rule for the areas, is

$\frac { d } { 2 }$ [h₁ + h_n + 2(h₃ + h₅ + ... + h_{n - 2}) + 4(h₂ + h₄ + ... + h_{n - 1})]

$\frac { d } { 3}$ [h₁ + h_n + 2(h₃ + h₅ + ... + h_{n - 2}) + 4(h₂ + h₄ + ... + h_{n - 1})]

$\frac { d } {6 }$ [h₁ + h_n x 2(h₂ + h₄ + ... + h_{n - 1}) + 4(h₃ + h₅ + ... + h_{n - 2})]

$\frac { d } {6 }$ [h₁ + h_n + 2(h₃ + h₅ + ... + h_{n - 2}) + 4(h₂ + h₄ + ... + h_{n - 1})]

none of these.

Answer : Option B

Explanation :

No answer description available for this question.

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