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The distance between the point of intersection of an up grade + g₁% and downgrade g2% and the highest point of the vertical curve of length L, is

$\frac { L(g1-g2) } { 400 }$

$\frac { L(g1+g2) } { 400 }$

$\frac { L(g1+g2) } { 800 }$

$\frac { L(g1-g2) } { 800 }$

Answer : Option D

Explanation :

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