Discussion :: Theory of Structures
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Ab and Ac are the cross sections of bronze and copper bars of equal length, σb, σc are their respective stresses due to load P. If Pb and Pc are the loads shared by them, (where Eb and Ec are their modulii)
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A.
\( \frac { σb } { σc } \)= \( \frac { Eb } { Ec } \) |
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B.
P = Pb + Pc |
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C.
P = Ab σb + Ac σb |
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D.
all the above |
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Answer : Option D
Explanation :
No answer description available for this question.
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