Discussion :: Waste Water Engineering
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For a circular sewer of diameter D running partially full with central angle α,
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A.
dD = 12 [ 1- cos \frac { α } { 2 } ] |
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B.
\frac { a} { A } = [ \frac { n} { 360^0 } - \frac { sina } { 2n } ] |
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C.
\frac { D } { P } = [ \frac { α} { 360^0 } |
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D.
\frac { r } { R } = [ 1- \frac { 360^0 sinα} { 2nα } ] |
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E.
all the above. |
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Answer : Option E
Explanation :
No answer description available for this question.
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