Discussion :: Communication Systems
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Consider a sampled signal y(t) = 5 x 10-6 x(t)
where x(t) = 10 cos (8p x 103)t and ts = 100 μ sec. when y(t) is passed through an ideal low-pass filter with a cut off frequency of 5 kHz, the output of the filter is
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A.
5 x 10-6 cos (8p x 103)t
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B.
5 x 10-5 cos (8p x 103)t
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C.
5 x 10-1 cos(8p x 103)t
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D.
10 cos(8p x 103)t
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Answer : Option B
Explanation :
No answer description available for this question.
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