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  1. Decimal number 46 in excess 3 code =

    2. A.
    1000 1001
    B.
    0111 1001
    C.
    0111 1111
    D.
    1000 1111

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    Answer : Option B

    Explanation :

    Decimal 46 in excess 3 code = 46 + 33 = 79 in decimal = 0111 1001 in 4 bit binary.

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