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  1. Two identical silicon diodes D1 and D2 are connected back to back shown in figure. The reverse saturation current Is of each diode is 10-8 amps and the breakdown voltage VBr is 50 v. Evaluate the voltages VD1 and VD2 dropped across the diodes D1 and D2 assuming KT/q to be 25 m V.

    2. A.
    4.983 V, 0.017 V
    B.
    - 4.98 V, - 0.017 V
    C.
    0.17 V, 4.983 V
    D.
    - 0.017 V, - 4.98 V

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    Answer : Option B

    Explanation :

    According to figure, D2 is forward bias, D1 is reverse biased. Reverse saturation current I0 = 10-8A. in clockwise direction.

    For Diode D2 Is = I0

    Here Is = I0

    eqv2/kT = 2 or ev2/0.026 = 2

    V2 = 0.018 V

    Drop across D1 = V1 = 5 - 0.018

    4.98 V

    By KVL in mesh, VD1 = -4.98 V, VD2 = 0.018 V.

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